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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    Molar heat of vaporisation of a liquid is \[6kJ\,mo{{l}^{-1}}\]. If the entropy change is \[16J\,mo{{l}^{-1}}\,{{K}^{-1}}\], the boiling point of the liquid is [KCET 2005]

    A)                 \[{{375}^{o}}C\]               

    B)                 \[375K\]

    C)                 \[273K\]              

    D)                 \[{{102}^{o}}C\]

    Correct Answer: B

    Solution :

               \[\Delta S=16J\,mol{{e}^{-1}}{{K}^{-1}}\]                                 \[{{T}_{b.p.}}=\frac{\Delta {{H}_{\text{vapour}}}}{\Delta {{S}_{\text{vapour}}}}=\frac{6\times 1000}{16}=375K\]


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