A) \[C{{H}_{4}}(g)+1/2{{O}_{2}}(g)\to C{{H}_{3}}OH(g)\]
B) C (graphite) \[+1/2{{O}_{2}}(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]
C) C (diamond) \[+1/2{{O}_{2}}(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]
D) \[CO(g)+2{{H}_{2}}(g)\to C{{H}_{3}}OH(l)\]
Correct Answer: B
Solution :
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