A) ? 121 KJ / mole
B) + 121 KJ / mole
C) ? 242 KJ / mole
D) + 242 KJ / mole
Correct Answer: A
Solution :
(i) \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}O,\,\,\Delta H=-241\,kJ\] (ii) \[{{C}_{6}}{{H}_{10}}+\frac{17}{2}{{O}_{2}}\to 6C{{O}_{2}}+5{{H}_{2}}O,\,\Delta H=-3800\,kJ\] (iii) \[{{C}_{6}}{{H}_{12}}+9{{O}_{2}}\to 6C{{O}_{2}}+6{{H}_{2}}O,\,\,\Delta H=-3920\,kJ\] \[{{C}_{6}}{{H}_{10}}+{{H}_{2}}\to {{C}_{6}}{{H}_{12}}\] Eq. (i) + Eq. (ii) ? Eq. (iii) \[\Delta H=-241-3800-(-3920)\] \[=-4041+3920=-121\,kJ\]
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