A) ? 241.8 kJ
B) 241.8 kJ
C) 329.8 kJ
D) ?329.8 kJ
Correct Answer: A
Solution :
\[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}{{O}_{(l)}};\,\,\,\Delta H=-285.8\,KJ\] \[{{H}_{2}}{{O}_{(l)}}\to {{H}_{2}}{{O}_{(g)}};\,\,\,\Delta H=44\,KJ\] \[\therefore {{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}{{O}_{(g)}}; & \,\,\,\Delta {{H}^{o}}=-241.8\,KJ\]You need to login to perform this action.
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