A) + 5.3 kJ/mol
B) + 6.2 kJ/mol
C) + 8.2 kJ/mol
D) + 9.3 kJ/mol
Correct Answer: A
Solution :
\[\Delta H=\,\Delta {{H}_{\text{ioniz}}}+\Delta {{H}_{\text{n}eu}}\] = \[-\,50.6\,\,=\,\Delta {{H}_{\text{ioniz}}}+(-55.9)\] \[\Delta {{H}_{\text{ioniz}}}=+\,5.3\,kJ/mol\].You need to login to perform this action.
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