question_answer

The enthalpy of formation of ammonia is \[-46.0\,kJ\,mo{{l}^{-1}}\]. The enthalpy change for the reaction \[2N{{H}_{3}}(g)\to 2{{N}_{2}}(g)+3{{H}_{2}}(g)\] is

A)                 46.0 kJ \[mo{{l}^{-1}}\]

B)                 92.0 kJ \[mo{{l}^{-1}}\]

C)                 ? 23.0 kJ \[mo{{l}^{-1}}\]             

D)                 ? 92.0 kJ \[mo{{l}^{-1}}\]