JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    The standard heats of formation in kcal \[mo{{l}^{-1}}\] of \[N{{O}_{2}}(g)\] and \[{{N}_{2}}{{O}_{4}}(g)\] are 8.0 and 2.0 respectively. The heat of dimerization of \[N{{O}_{2}}\] in \[kcal\] is                 \[2N{{O}_{2}}(g)={{N}_{2}}{{O}_{4}}(g)\]                                              [NCERT 1983]

    A)                 10.0       

    B)                 ? 6.0

    C)                 ? 12.0   

    D)                 ? 14.0

    Correct Answer: D

    Solution :

               \[\Delta {{H}_{\text{reaction}}}=\Delta H_{f}^{0}\,({{N}_{2}}{{O}_{4}})-2\Delta H_{f}^{0}\,(N{{O}_{2}})\]                                          \[=2-2\,(8)=-14\,\,kcal.\]


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