JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Heat of reaction

  • question_answer
    The difference between heats of reaction at constant pressure and at constant volume for the reaction \[2{{C}_{6}}{{H}_{6}}(l)+15{{O}_{2}}(g)\to 12C{{O}_{2}}(g)+6{{H}_{2}}O(l)\]at \[{{25}^{o}}C\]in kJ is [IIT JEE 1991; Kerala PMT 2004]

    A)                 ?7.43    

    B)                 + 3.72

    C)                 ?3.72    

    D)                 + 7.43

    Correct Answer: A

    Solution :

           \[\Delta H-\Delta E=\Delta nRT\]\[=3\times 8.314\,\,\times 298\]                         \[=-7432\,\,J=-7.43\,kJ.\]


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