A) \[C(diamond)\,+2{{H}_{2}}(g)=C{{H}_{4}}(g)\]
B) \[C(graphite)+2{{H}_{2}}(g)=C{{H}_{4}}(l)\]
C) \[C(graphite)+2{{H}_{2}}(g)=C{{H}_{4}}(g)\]
D) \[C(graphite)+4H=C{{H}_{4}}(g)\]
Correct Answer: C
Solution :
\[{{C}_{(\text{graphite})}}+2{{H}_{2(g)}}=C{{H}_{4(g)}}\].
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