A) \[+1412\,kJ\,mo{{l}^{-1}}\]
B) \[-1412\,kJ\,mo{{l}^{-1}}\]
C) \[+141.2\,kJ\,mo{{l}^{-1}}\]
D) \[-141.2\,kJ\,mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{4}}+3{{O}_{2}}\to 2C{{O}_{2}}+2{{H}_{2}}O\] \[\Delta {{H}_{\text{reaction}}}=[2\times \Delta H_{f}^{o}(C{{O}_{2}})+2\times \Delta H_{f}^{o}\,({{H}_{2}}O)]\] \[-[\Delta H_{f}^{o}\,({{C}_{2}}{{H}_{4}})+\,3\,\,\times \Delta H_{f}^{o}\,({{O}_{2}})]\] \[=[\,2\,(\,-394)+2\,(\,-286)]-[52+0]=-1412\,kJ\].
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