A) \[+94\,kcal\]
B) \[-\,94\,kcal\]
C) \[+47\,kcal\]
D) \[-47\,kcal\]
Correct Answer: B
Solution :
\[{{C}_{(S)}}+{{O}_{2}}_{(g)}\to C{{O}_{2}}_{(g)}\], \[\Delta {{n}_{g}}=1-1=0\] \[\therefore \Delta E=\Delta H=-94\,\,kcal\] \[\Delta E={{E}_{C{{O}_{2}}}}-({{E}_{C}}+{{E}_{{{O}_{2}}}})\]\[={{E}_{C{{O}_{2}}}}-(0+0)\] or \[{{E}_{C{{O}_{2}}}}=\Delta E=-94\,\,kcal.\]You need to login to perform this action.
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