A) 10 ohm
B) 20 ohm
C) 30 ohm
D) 40 ohm
Correct Answer: C
Solution :
Suppose resistance R is corrected in series with bulb. Current through the bulb \[i=\frac{90}{30}=3\,A\] Hence for resistance \[V=i\,R\]Þ \[90=3\times R\Rightarrow R=30\,\Omega \]You need to login to perform this action.
You will be redirected in
3 sec