A) 2 : 1
B) 1 : 2
C) 1 : 4
D) 4 : 1
Correct Answer: C
Solution :
\[P=\frac{{{V}^{2}}}{R}\]. If resistance of heater coil is R, then resistance of parallel combination of two halves will be \[\frac{R}{4}\] So \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{R/4}{R}=\frac{1}{4}\]You need to login to perform this action.
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