• # question_answer 3 identical bulbs are connected in series and these together dissipate a power P. If now the bulbs are connected in parallel, then the power dissipated will be        [DPMT 2005] A)            $\frac{P}{3}$                      B)            3P C)            9P   D)            $\frac{P}{9}$

Correct Answer: C

Solution :

When bulbs are connected in series, $P=\frac{{{V}^{2}}}{{{R}'}}=\frac{{{V}^{2}}}{3R}$ When bulbs are connected in parallel, ${P}'=\frac{{{V}^{2}}}{{{R}''}}=\frac{{{V}^{2}}\times 3}{R}=3\times 3P=9P.$

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