• # question_answer Two bulbs are in parallel and they together consume 48 W from a battery of 6 V. The resistance of each bulb is A)            $0.67\,\Omega$              B)            $3.0\,\Omega$ C)            $4.0\,\Omega$                 D)            $1.5\,\Omega$

The bulbs are connected in parallel, hence each bulb consumes $\frac{48}{2}=24\,W.$ Therefore $\frac{{{V}^{2}}}{R}=24\,$ Þ $R=\frac{6\times 6}{24}=1.5\,\Omega$