• question_answer A 100 watt bulb working on 200 volt and a 200 watt bulb working on 100 volt have A)            Resistances in the ratio of 4 : 1 B)            Maximum current ratings in the ratio of $1:4$ C)            Resistances in the ratio of 2 : 1 D)            Maximum current ratings in the ratio of 1 : 2

Solution :

$R=\frac{{{V}^{2}}}{P}$ Þ ${{R}_{1}}=\frac{200\times 200}{100}=400\,\Omega$ and ${{R}_{2}}=\frac{100\times 100}{200}=50\,\Omega .$ Maximum current rating $i=\frac{P}{V}$ So ${{i}_{1}}=\frac{100}{200}$ and${{i}_{2}}=\frac{200}{100}$Þ $\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{1}{4}$.

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