• # question_answer Two conductors made of the same material are connected across a common potential difference. Conductor A has twice the diameter and twice the length of conductor B. The power delivered to the two conductors ${{P}_{A}}$ and ${{P}_{B}}$ respectively is such that ${{P}_{A}}/{{P}_{B}}$ equals to A)            0.5  B)            1.0 C)            1.5  D)            2.0

$R=\rho \frac{l}{A}$and$P\propto \frac{1}{R}$Þ$P\propto \frac{A}{l}$Þ$P\propto \frac{{{d}^{2}}}{l}$Þ ${{P}_{A}}=2{{P}_{B}}$