• # question_answer Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio [NCERT 1977; MP PMT 1994, 2000] A)            1 : 2                                           B)            1 : 1 C)            2 : 1                                           D)            1 : 4

We know that $\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{2}{1}$