A) \[R\sin \alpha \]
B) \[R\cos \alpha \]
C) \[R\cot \alpha \]
D) \[R\tan \alpha \]
Correct Answer: D
Solution :
Since the tower makes equal angles at the vertices of the triangle, therefore foot of the tower is at the circumcentre. From \[\Delta OAP,\] we have \[\tan \alpha =\frac{OP}{OA}\] \[\Rightarrow \] \[OP=OA\tan \alpha \] \[\Rightarrow \] \[OP=R\tan \alpha \].You need to login to perform this action.
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