A) 20 m
B) 40 m
C) 30 m
D) 60 m
Correct Answer: A
Solution :
\[b=h\cot {{60}^{o}},\,b+40=h\cot {{30}^{o}}\] \[\Rightarrow \] \[\frac{b}{b+40}=\frac{\cot {{60}^{o}}}{\cot {{30}^{o}}}\] \[\Rightarrow \] \[b=20m\].You need to login to perform this action.
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