A) \[\frac{5h}{3}\]
B) \[\frac{4h}{3}\]
C) \[\frac{7h}{5}\]
D) \[\frac{3h}{2}\]
Correct Answer: A
Solution :
\[\tan \alpha =\frac{1}{2}\] and \[BC=a\text{ }km\] \[\tan 2\alpha =\frac{2\tan \alpha }{1-{{\tan }^{2}}\alpha }\Rightarrow \frac{p+h}{2h}=\frac{1}{1-\frac{1}{4}}\] \[\Rightarrow \] \[\frac{p+h}{2h}=\frac{4}{3}\Rightarrow p=\frac{5h}{3}\].You need to login to perform this action.
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