A) h/3
B) h/3d
C) 3h
D) \[\frac{3h}{d}\]
Correct Answer: A
Solution :
Trick: From\[H=l\tan \alpha \,.\,\tan \beta \], the height of tower is \[h\tan {{30}^{o}}\cot {{60}^{o}}\text{or }\frac{h}{3}\].You need to login to perform this action.
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