A) 40 m
B) \[40\sqrt{3}\,m\]
C) 68.280 m
D) 109.28 m
Correct Answer: D
Solution :
From \[\Delta \text{ }{{O}_{1}}AB,\] \[\tan {{45}^{o}}=\frac{40}{x}\Rightarrow x=40m\] From \[\Delta A{{O}_{2}}B,\] \[\cot {{30}^{o}}=\frac{y}{40}\] \[\Rightarrow \] \[y=40\,\] cot \[{{30}^{o}}=40\sqrt{3}\] Distance between the men = \[40+40\sqrt{3}=109.28\] m.You need to login to perform this action.
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