A) \[\frac{2}{11}\]
B) \[\frac{2}{21}\]
C) \[\frac{21}{2}\]
D) \[\frac{21}{4}\]
Correct Answer: B
Solution :
Let\[\angle BAC=\beta \], \[{{H}_{1}}=d\tan {{60}^{o}},\] Now \[\tan (\alpha +\beta )=\frac{100}{50}\] Þ \[\frac{\tan \alpha +\tan \beta }{1-\tan \alpha \tan \beta }=2\] Þ \[\frac{\tan \alpha +\frac{8}{5}}{1-\frac{8}{5}\tan \alpha }=2\] \[\Rightarrow \tan \alpha =\frac{2}{21}\].You need to login to perform this action.
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