A) \[{{60}^{o}}\]
B) \[{{80}^{o}}\]
C) \[{{75}^{o}}\]
D) None of these
Correct Answer: A
Solution :
Accordingly, \[\tan \theta =\frac{h}{x}=\frac{h+6}{x+2\sqrt{3}}=\frac{6}{2\sqrt{3}}\Rightarrow \theta ={{60}^{o}}\][Since the triangles \[60-x=\sqrt{3}(\sqrt{3}x)\] and \[\frac{60}{4}=x\Rightarrow x=15\] are similar].You need to login to perform this action.
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