A) \[\frac{18}{19}\]
B) \[\frac{3}{19}\]
C) \[\frac{1}{6}\]
D) None of these
Correct Answer: B
Solution :
Let\[AC=x=CB,\,AP=3AB=6x\]. Let \[2x=2n\pi \pm \left( \frac{\pi }{2}-2x \right)\] In \[\Delta ACP,\,\tan \alpha =\frac{x}{6x}=\frac{1}{6}\]You need to login to perform this action.
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