A) 10 m
B) \[(2\sqrt{3}-3)\,20\,\,m\]
C) \[\frac{20}{3}m\]
D) None of these
Correct Answer: C
Solution :
\[H=20=l+h,\,l=\frac{d}{\cos {{30}^{o}}},\,h=d\tan {{30}^{o}}\] \[\therefore \] \[d=\frac{20}{(\sec {{30}^{o}}+\tan {{30}^{o}})}=\frac{20}{\sqrt{3}}\] and hence \[h=d\tan {{30}^{o}}=\frac{20}{3}m\].You need to login to perform this action.
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