A) \[48\,\sqrt{3}\,\,m\]
B) \[16\,\sqrt{3}\,\,m\]
C) \[24\,\sqrt{3}\,\,m\]
D) \[16/\,\sqrt{3}\,\,m\]
Correct Answer: B
Solution :
\[h=12\tan {{30}^{o}}=\frac{12}{\sqrt{3}}\] and \[H=12\tan {{60}^{o}}+\frac{12}{\sqrt{3}}\] = \[12\sqrt{3}+\frac{12}{\sqrt{3}}=16\sqrt{3}m\].You need to login to perform this action.
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