A) \[x=y\tan \frac{\alpha +\beta }{2}\]
B) \[y=x\tan \frac{\alpha +\beta }{2}\]
C) \[x=y\tan (\alpha +\beta )\]
D) \[y=x\tan (\alpha +\beta )\]
Correct Answer: A
Solution :
\[PB=QC=l\] (Length of ladder) \[\Rightarrow \] \[PA=l\cos \alpha ,\,QA=l\,\cos \beta \]You need to login to perform this action.
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