A) \[\frac{\sin 3\alpha }{\sin 2\alpha }\]
B) \[1+2\cos 2\alpha \]
C) \[2+\cos 3\alpha \]
D) \[\frac{\sin 2\alpha }{\sin \alpha }\]
Correct Answer: B
Solution :
From sine rule,You need to login to perform this action.
You will be redirected in
3 sec