A) \[48\sqrt{2}sq.m\]
B) \[48\sqrt{3}sq.m\]
C) \[48sq.m\]
D) \[12\sqrt{2}sq.m\]
E) \[12\sqrt{3}sq.m\]
Correct Answer: A
Solution :
Let AE is a vertical lamp-post. Given, \[AE=12\]m \[\tan {{45}^{o}}=\frac{AE}{AC}\]You need to login to perform this action.
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