A) 15 cm
B) 14 cm
C) 12 cm
D) 13 cm
Correct Answer: C
Solution :
For the given triangle, we have a = 28 cm, b = 30 cm, c = 26 cm So, \[s=\frac{a+b+c}{2}=\frac{28+30+26}{2}\] \[s=\frac{a+b+c}{2}=\frac{28+30+26}{2}\] \[=\frac{84}{2}=42\,cm\] Area of the triangle \[=\sqrt{42(42-28)(42-30)(42-26)}\,c{{m}^{2}}\] \[=\sqrt{42\times 14\times 12\times 16}\,c{{m}^{2}}\] \[=\sqrt{112896}\,c{{m}^{2}}=336\,c{{m}^{2}}\] Area of the parallelogram = Area of the triangle \[\therefore \]Area of the parallelogram \[=336\,c{{m}^{2}}\] \[\Rightarrow \]\[base\times height=336\Rightarrow 28\times h=336\] \[\Rightarrow \]\[h=\frac{336}{28}\,cm=12\,cm\] Thus, the height of the parallelogram = 12 cmYou need to login to perform this action.
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