A) 12sq.cm
B) 36 sq.cm
C) 24 sq.cm
D) 48 sq.cm
Correct Answer: D
Solution :
Let the equal sides of an isosceles triangle be \[x\]cm. Its perimeter is \[x+x+12=32\Rightarrow x=10\,cm\] Area of the triangle is \[\Delta =\sqrt{16(16-10)(16-10)(16-12)}\] \[=8\times 6=48\,sq.\,cm\]You need to login to perform this action.
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