A) + 0.5 D
B) + 1.0 D
C) + 2.0 D
D) ? 1.0 D
Correct Answer: D
Solution :
The image of object at infinity should be formed at 100 cm from the eye \[\frac{1}{f}=\frac{1}{\infty }-\frac{1}{100}=-\frac{1}{100}\] So the power \[=\frac{-100}{100}=-\ 1\]D (Distance is given in cm but \[P=\frac{1}{f}\] in metres)You need to login to perform this action.
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