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JEE Main & Advanced Physics Question Bank Human Eye and Lens Camera

  • question_answer
    A presbyopic patient has near point as 30 cm and far point as 40 cm. The dioptric power for the corrective lens for seeing distant objects is  

    A)            40 D                                         

    B)    4 D  

    C)    ? 2.5 D

    D)            0.25 D  

    Correct Answer: C

    Solution :

                       In this case, for seeing distant objects the far point is 40 cm. Hence the required focal length is                    \[f=-\ d\](distance of far point) = ? 40 cm            Power \[P=\frac{100}{f}cm=\frac{100}{-40}=-\ 2.5\ D\]


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