A) 0.4 sec
B) 0.02 sec
C) 0.002 sec
D) 0.04 sec
Correct Answer: B
Solution :
Time of exposure \[\propto {{(f.\,number)}^{2}}\] \[\Rightarrow \frac{{{t}_{2}}}{{{t}_{1}}}={{\left( \frac{5.6}{2.8} \right)}^{2}}=4\] \[{{t}_{2}}=4\,{{t}_{1}}=4\times \frac{1}{200}=\frac{1}{50}\]sec = 0.02 sec.You need to login to perform this action.
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