A) 40 D
B) 4 D
C) ? 2.5 D
D) 0.25 D
Correct Answer: C
Solution :
In this case, for seeing distant objects the far point is 40 cm. Hence the required focal length is \[f=-\ d\](distance of far point) = ? 40 cm Power \[P=\frac{100}{f}cm=\frac{100}{-40}=-\ 2.5\ D\]You need to login to perform this action.
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