A) \[[Co{{(N{{H}_{3}})}_{5}}Cl]\,C{{l}_{2}}\]
B) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}].\,2N{{H}_{3}}\]
C) \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]\,Cl\,.\,N{{H}_{3}}\]
D) \[[Co{{(N{{H}_{3}})}_{4}}Cl]\,C{{l}_{2}}.\,N{{H}_{3}}\]
Correct Answer: A
Solution :
\[2C{{l}^{-}}\] ions are ionizable \[\therefore \,\left[ Co{{(N{{H}_{3}})}_{5}}Cl \right]C{{l}_{2}}\] ⇌ \[\underbrace{{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{\,2+}}+2C{{l}^{-}}}_{3\text{ ions}}\] \[2C{{l}^{-}}+2AgN{{O}_{3}}\to 2AgCl+2NO_{3}^{-}\].You need to login to perform this action.
You will be redirected in
3 sec