A) \[s{{p}^{3}}\] hybridised
B) \[ds{{p}^{2}}\]hybridised
C) \[s{{p}^{3}}d\] hybridised
D) \[s{{p}^{3}}{{d}^{2}}\] hybridized
Correct Answer: B
Solution :
Due to formation of inner orbital complex.You need to login to perform this action.
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