A) \[BF_{4}^{-}\]
B) \[S{{F}_{4}}\]
C) \[Xe{{F}_{4}}\]
D) \[{{\left[ Ni{{(CN)}_{4}} \right]}^{2-}}\] (Atomic no. : \[B=5,S=16,Ni=28,Xe=54\])
Correct Answer: A
Solution :
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