A) \[N{{O}_{2}}\]-\[sp\], \[S{{F}_{4}}\]-\[s{{p}^{2}}\], \[PF_{6}^{-}\]-\[s{{p}^{3}}\]
B) \[N{{O}_{2}}\]-\[sp\], \[S{{F}_{4}}\]-\[s{{p}^{3}}d\], \[PF_{6}^{-}\]-\[s{{p}^{3}}{{d}^{2}}\]
C) \[N{{O}_{2}}\]-\[s{{p}^{2}}\], \[S{{F}_{4}}\]-\[s{{p}^{3}}\], \[PF_{6}^{-}\]-\[{{d}^{2}}s{{p}^{3}}\]
D) \[N{{O}_{2}}\]-\[s{{p}^{3}}\], \[S{{F}_{4}}\]-\[s{{p}^{3}}{{d}^{2}}\], \[PF_{6}^{-}\]-\[s{{p}^{3}}{{d}^{2}}\]
Correct Answer: B
Solution :
\[\underset{sp}{\mathop{N{{O}_{2}}}}\,\ \ \underset{s{{p}^{3}}d}{\mathop{S{{F}_{4}}}}\,\ \ \ \underset{s{{p}^{3}}{{d}^{2}}}{\mathop{PF_{6}^{-}}}\,\]You need to login to perform this action.
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