question_answer

The correct order of bond angles (smallest first) in \[{{H}_{2}}S,N{{H}_{3}},B{{F}_{3}}\]and \[Si{{H}_{4}}\]is          [AIEEE 2004]

A)                 \[{{H}_{2}}S<N{{H}_{3}}<Si{{H}_{4}}<B{{F}_{3}}\]

B)                 \[N{{H}_{3}}<{{H}_{2}}S<Si{{H}_{4}}<B{{F}_{3}}\]

C)                 \[{{H}_{2}}S<Si{{H}_{4}}<N{{H}_{3}}<B{{F}_{3}}\]

D)                 \[{{H}_{2}}S<N{{H}_{3}}<B{{F}_{3}}<Si{{H}_{4}}\]

Correct Answer: C

Solution :

           The correct order of bond angle (Smallest first) is            \[{{H}_{2}}S<N{{H}_{3}}<Si{{H}_{4}}<B{{F}_{3}}\]            \[92.6{}^\circ <107{}^\circ <109{}^\circ 28'<120{}^\circ \]