A) \[Be{{F}_{3}}^{-}\]
B) \[OH_{3}^{+}\]
C) \[N{{H}_{2}}^{-}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
Correct Answer: A
Solution :
In \[BeF_{3}^{-}\], Be is not \[s{{p}^{3}}\]?hybridised it is \[s{{p}^{2}}\] hybridised.You need to login to perform this action.
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