A) \[s{{p}^{3}}{{d}^{2}}\]
B) \[s{{p}^{3}}\]
C) \[s{{p}^{3}}d\]
D) \[s{{p}^{2}}d\]
Correct Answer: A
Solution :
\[Xe{{F}_{4}}\] has \[s{{p}^{3}}{{d}^{2}}\] hybridisation, its shape is square planar.You need to login to perform this action.
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