A) \[PC{{l}_{3}}\]
B) \[S{{O}_{3}}\]
C) \[B{{F}_{3}}\]
D) \[NO{}_{3}^{-}\]
Correct Answer: A
Solution :
\[PC{{l}_{3}}\] contain three bonding and one lone pair electron. Hence shows \[s{{p}^{3}}\]?hybridization.You need to login to perform this action.
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