A) \[{{10}^{-11}}\]
B) 3
C) 14
D) 11
Correct Answer: D
Solution :
0.001 M KOH solution \[[O{{H}^{-}}]=0.001\,M=1\times {{10}^{-3}}M\] \[[{{H}^{+}}]\times [O{{H}^{-}}]=1\times {{10}^{-14}}\] \[[{{H}^{+}}]=\frac{1\times {{10}^{-14}}}{[O{{H}^{-}}]}\] \[[{{H}^{+}}]=\frac{1\times {{10}^{-14}}}{1\times {{10}^{-3}}}\]\[=1\times {{10}^{-14}}\times {{10}^{+3}}\] \[[{{H}^{+}}]={{10}^{-11}}\]M \[pH=11\]You need to login to perform this action.
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