A) 0.3979
B) 1.3979
C) 1.699
D) 3.3979
Correct Answer: D
Solution :
\[[{{H}^{+}}]=\alpha .C\,\,=\frac{2}{100}\times .02\]; \[[{{H}^{+}}]=4\times {{10}^{-4}}\]M \[pH=-\log \,\,[{{H}^{+}}]=4-\log \,\,4\]; \[pH=3.3979\]You need to login to perform this action.
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