A) 6
B) 13
C) 18
D) 24
Correct Answer: B
Solution :
\[[NaOH]=0{.4}/{40\,\,{mole}/{l.}\;=0.1\,M}\;\] \[[O{{H}^{-}}]={{10}^{-1}}M\], \[[{{H}^{+}}]={{10}^{-13}}M\],\[pH=13\]You need to login to perform this action.
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