A) Zero
B) \[1\times {{10}^{7}}\,gm\,\,ion/litre\]
C) \[1\times {{10}^{-14}}\,gm\,\,ion/litre\]
D) \[1\times {{10}^{-7}}\,gm\,\,ion/litre\]
Correct Answer: D
Solution :
\[{{H}_{3}}{{O}^{+}}\] ⇌ \[O{{H}^{-}}+{{H}_{2}}\] \[pOH+pH=14\] ; \[7+7=14\]; \[[{{H}^{+}}]+[O{{H}^{-}}]={{10}^{-14}}\] \[{{10}^{-7}}+{{10}^{-7}}={{10}^{-14}}\]; \[[O{{H}^{-}}]={{10}^{-7}}\]gm ion/l.You need to login to perform this action.
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