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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Hydrogenion concentration pH scale and buffer solution

  • question_answer
    0.1 mole of CH3NH2 (Kb = 5 ´ 10-4) is mixed with 0.08 mole of HCl and diluted to one litre. What will be the H+ concentration in the solution?                         [IIT 2005]

    A)                 8 ´ 10-2 M          

    B)                 8 ´ 10-11 M

    C)                 1.6 ´ 10-11 M     

    D)                 8 ´ 10-5 M

    Correct Answer: B

    Solution :

               CH3NH2 + HCl \[\xrightarrow{{}}\] \[C{{H}_{3}}NH_{3}^{+}C{{l}^{-}}\]                    0.1            0.08                 0                    0.02            0                     0.08                                            (Basic buffer solution)                    pOH = pKb + log \[\frac{0.08}{0.02}\]                        = pKb + 0.602                        = 3.30 + 0.602= 3.902                    \ pH   = 10.09                                 [H+]  = 7.99 ´ 10-11 » 8 ´ 10-11 M


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